{"id":17928,"date":"2024-03-02T18:01:56","date_gmt":"2024-03-02T18:01:56","guid":{"rendered":"https:\/\/soicau1023.minhngocxoso.com\/cach-bat-cac-tong-de-trong-lo-de-so-de-mien-bac-hay-hien-nay\/"},"modified":"2024-03-02T18:01:56","modified_gmt":"2024-03-02T18:01:56","slug":"cach-bat-cac-tong-de-trong-lo-de-so-de-mien-bac-hay-hien-nay","status":"publish","type":"post","link":"https:\/\/soicauxien.com\/cach-bat-cac-tong-de-trong-lo-de-so-de-mien-bac-hay-hien-nay\/","title":{"rendered":"C\u00e1ch b\u1eaft c\u00e1c t\u1ed5ng \u0111\u1ec1 trong l\u00f4 \u0111\u1ec1, s\u1ed1 \u0111\u1ec1 mi\u1ec1n B\u1eafc hay hi\u1ec7n nay"},"content":{"rendered":"
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1<\/strong><\/span> trong ch\u01a1i l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p kh\u00e1 \u0111\u01b0\u1ee3c \u01b0a chu\u1ed9ng b\u1edfi nh\u1eefng ng\u01b0\u1eddi ch\u01a1i chuy\u00ean nghi\u1ec7p, v\u1ec1 c\u01a1 b\u1ea3n th\u00ec khi b\u1eaft t\u1ed5ng \u0111\u1ec1 c\u0169ng \u0111\u01b0\u1ee3c chia ra l\u00e0m 2 d\u1ea1ng l\u00e0 \u0111\u01a1n gi\u1ea3n v\u00e0 c\u1ea7n \u0111\u1ea7u \u00f3c t\u00ednh to\u00e1n k\u1ef9 c\u00e0ng.<\/span><\/span><\/span><\/p>\n Trong b\u00e0i n\u00e0y, ch\u00fang t\u00f4i s\u1ebd gi\u1edbi thi\u1ec7u cho b\u1ea1n 6 c\u00e1ch b\u1eaft c\u00e1c t\u1ed5ng trong l\u00f4 \u0111\u1ec1 \u0111\u00e3 \u0111\u01b0\u1ee3c ch\u1ee9ng minh l\u00e0 s\u1ebd gi\u00fap cho ng\u01b0\u1eddi ch\u01a1i t\u0103ng t\u1ef7 l\u1ec7 tr\u00fang l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc l\u00ean cao nh\u1ea5t.<\/span><\/span><\/span><\/p>\n Theo kinh nghi\u1ec7m c\u1ee7a nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i tr\u01b0\u1edbc \u0111\u00e2y th\u00ec \u0111\u00e3 ki\u1ec3m ch\u1ee9ng r\u1eb1ng khi t\u1ed5ng c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ra r\u01a1i v\u00e0o m\u1ed9t s\u1ed1 tr\u01b0\u1eddng h\u1ee3p d\u01b0\u1edbi \u0111\u00e2y th\u00ec b\u1ea1n c\u00f3 th\u1ec3 \u0111\u00e1nh d\u00e0n t\u1ed5ng t\u01b0\u01a1ng \u1ee9ng:<\/span><\/span><\/span><\/p>\n – T\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 9 th\u00ec h\u00f4m sau \u0111a ph\u1ea7n tr\u1ea3 v\u1ec1 t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 5.<\/span><\/span><\/span><\/p>\n – T\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 10 th\u00ec h\u00f4m sau s\u1ebd tr\u1ea3 v\u1ec1 t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 1.<\/span><\/span><\/span><\/p>\n – T\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 6 th\u00ec h\u00f4m sau s\u1ebd tr\u1ea3 v\u1ec1 t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 8.<\/span><\/span><\/span><\/p>\n T\u1eeb \u0111\u00f3, b\u1ea1n c\u00f3 th\u1ec3 \u0111\u00e1nh d\u00e0n \u0111\u1ec1 t\u01b0\u01a1ng \u1ee9ng, v\u00ed d\u1ee5 nh\u01b0 t\u1ed5ng 5 c\u00f3 d\u00e0n 050, 141, 232.<\/span><\/span><\/span><\/p>\n <\/p>\n C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 mi\u1ec1n B\u1eafc hay th\u00f4ng qua b\u1ea1c nh\u1edb<\/span><\/em><\/span><\/span><\/p>\n \u0110\u1ec3 xem nh\u1eefng c\u00e1ch soi c\u1ea7u mi\u1ec1n B\u1eafc, c\u00e1c b\u1ea1n tham kh\u1ea3o t\u1ea1i \u0111\u00e2y: Soi c\u1ea7u XSMB mi\u1ec5n ph\u00ed ng\u00e0y h\u00f4m nay<\/span><\/strong><\/em><\/span><\/span><\/p>\n C\u00e1ch n\u00e0y \u0111\u01b0\u1ee3c t\u00ednh to\u00e1n nh\u01b0 sau: \u0110\u1ea7u ti\u00ean x\u00e1c \u0111\u1ecbnh m\u1ed1c ng\u00e0y b\u1eaft \u0111\u1ea7u t\u00ednh ta c\u00f3: Coi \u0111\u1ec1 ng\u00e0y th\u1ee9 nh\u1ea5t l\u00e0 AB, \u0111\u1ec1 v\u1ec1 ng\u00e0y th\u1ee9 hai l\u00e0 CD.<\/span><\/span><\/span><\/p>\n Ta c\u00f3 A + B = E; C + D = F.<\/span><\/span><\/span><\/p>\n X\u00e9t c\u00e1c tr\u01b0\u1eddng h\u1ee3p x\u1ea3y ra nh\u01b0 sau:<\/span><\/span><\/span><\/p>\n + Tr\u01b0\u1eddng h\u1ee3p 1: N\u1ebfu E < 10, F < 10 l\u1ea5y 10 – E = X, 10 – F = Y. \u0110\u00e1nh XY cho l\u00f4 ng\u00e0y th\u1ee9 3.<\/span><\/span><\/span><\/p>\n + Tr\u01b0\u1eddng h\u1ee3p 2: N\u1ebfu E > 10, F < 10 l\u1ea5y 20 – E = X, 10 – F = Y, \u0111\u00e1nh l\u00f4 XY ng\u00e0y th\u1ee9 3.<\/span><\/span><\/span><\/p>\n + Tr\u01b0\u1eddng h\u1ee3p 3: N\u1ebfu E > 10, F > 10 l\u1ea5y 20 – E = X, 20 – F = Y, \u0111\u00e1nh l\u00f4 ng\u00e0y th\u1ee9 3 l\u00e0 XY.<\/span><\/span><\/span><\/p>\n + Tr\u01b0\u1eddng h\u1ee3p 4: N\u1ebfu E < 10, F > 10. Ta l\u1ea5y hi\u1ec7u 10 – E = X, 20 – F = Y, ng\u00e0y th\u1ee9 3 \u0111\u00e1nh l\u00e0 YX.<\/span><\/span><\/span><\/p>\n + Tr\u01b0\u1eddng h\u1ee3p 5: E = 0 ho\u1eb7c 10, F = 0 ho\u1eb7c 10 th\u00ec X, Y \u0111\u1ec1u l\u00e0 0.<\/span><\/span><\/span><\/p>\n – C\u1ea7u n\u00e0y c\u00f3 th\u1ec3 \u0111\u00e1nh li\u00ean t\u1ee5c trong 3 – 4 ng\u00e0y.<\/span><\/span><\/span><\/p>\n – N\u1ebfu h\u00f4m sau \u0111\u00e1nh m\u00e0 kh\u00f4ng v\u1ec1 th\u00ec ngh\u1ec9 1 ng\u00e0y, nh\u01b0ng c\u1ea7u l\u1ea1i ra \u0111\u00fang h\u00f4m ngh\u1ec9 th\u00ec b\u1ecf c\u1ea7u lu\u00f4n, c\u00f2n n\u1ebfu v\u1eabn kh\u00f4ng ra th\u00ec h\u00f4m ti\u1ebfp s\u1ebd v\u1ec1.<\/span><\/span><\/span><\/p>\n – Tr\u01b0\u1eddng h\u1ee3p v\u1ec1 l\u1ed9n th\u00ec ngh\u1ec9 3, 4 ng\u00e0y r\u1ed3i m\u1edbi \u0111\u00e1nh l\u1ea1i c\u1ea7u n\u00e0y.<\/span><\/span><\/span><\/p>\n – N\u1ebfu c\u1ea7u n\u00e0y kh\u00f4ng v\u1ec1 trong 5, 6 ng\u00e0y th\u00ec ngh\u1ec9 ng\u00e0y th\u1ee9 7 sau \u0111\u00f3 \u0111\u00e1nh 3 ng\u00e0y ti\u1ebfp, th\u1ea5y ng\u00e0y th\u1ee9 7 ra th\u00ec \u0111\u00e1nh c\u1ea7u n\u00e0y v\u00e0o ng\u00e0y th\u1ee9 8.<\/span><\/span><\/span><\/p>\n Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 tham kh\u1ea3o th\u00eam c\u00e1c ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc hi\u1ec7u qu\u1ea3, \u0103n l\u00e3i cao t\u1ea1i: Ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh l\u00f4 \u0111\u1ec1<\/strong><\/em><\/p>\n C\u00e1ch soi c\u1ea7u l\u00f4 h\u00f4m nay<\/strong> n\u00e0y g\u1ed3m 2 c\u00e1ch c\u1ee5 th\u1ec3 sau: <\/span><\/span><\/span><\/p>\n – C\u00e1ch n\u00e0y kh\u00e1 quen thu\u1ed9c r\u1ed3i, c\u1ed9ng 5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0o, l\u1ea5y s\u1ed1 \u0111\u00f3 \u0111\u1ec3 l\u00e0m c\u1eb7p l\u00f4 \u0111\u00e1nh cho h\u00f4m sau, n\u00f3i chung l\u00e0 t\u1ef7 l\u1ec7 tr\u00fang t\u01b0\u01a1ng \u0111\u1ed1i.<\/span><\/span><\/span><\/p>\n – B\u1eaft l\u00f4 \u0111\u1ec1 th\u00f4ng qua c\u1ed9ng d\u1ed3n gi\u1ea3i \u0111\u1eb7c bi\u1ec7t tu\u1ea7n tr\u01b0\u1edbc, c\u00e1ch n\u00e0y c\u0169ng gi\u1edbi thi\u1ec7u kh\u00e1 nhi\u1ec1u n\u00ean m\u00ecnh kh\u00f4ng nh\u1eafc l\u1ea1i.<\/span><\/span><\/span><\/p>\n Anh em n\u00e0o ch\u01b0a r\u00f5 th\u00ec t\u00ecm c\u00e1ch c\u00e1ch n\u00e0y trong c\u00e1c b\u00e0i tr\u01b0\u1edbc nh\u00e9.<\/span><\/span><\/span><\/p>\n \n Ng\u01b0\u1eddi ch\u01a1i c\u00f3 th\u1ec3 tham kh\u1ea3o th\u00eam: C\u1ea7u mi\u1ec1n b\u1eafc soi t\u1eeb c\u1ea7u l\u00f4 gi\u1ea3i 7 h\u00f4m nay hi\u1ec7u qu\u1ea3 nh\u1ea5t<\/strong><\/em><\/p>\n Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 sau: <\/span><\/span><\/span><\/p>\n – D\u00f9ng 5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 5 s\u1ed1 gi\u1ea3i nh\u1ea5t gh\u00e9p l\u1ea1i v\u1edbi nhau, sau \u0111\u00f3 c\u1ed9ng ch\u00fang l\u1ea1i theo quy lu\u1eadt Pascal t\u1ee9c l\u00e0 c\u1ed9ng 3 s\u1ed1 li\u1ec1n nhau li\u00ean ti\u1ebfp.<\/span><\/span><\/span><\/p>\n – N\u1ebfu t\u1ed5ng l\u1edbp h\u01a1n 10 ch\u1ec9 l\u1ea5y s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb.<\/span><\/span><\/span><\/p>\n – C\u1ed9ng \u0111\u1ebfn khi ch\u1ec9 c\u00f2n l\u1ea1i 2 s\u1ed1 th\u00ec l\u1ea5y \u0111\u00e1nh l\u00f4 h\u00f4m sau.<\/span><\/span><\/span><\/p>\n – C\u1ea7u n\u00e0y nu\u00f4i trong 3 ng\u00e0y.<\/span><\/span><\/span><\/p>\n VD: Ng\u00e0y 21\/7\/2024 ta c\u00f3 G\u0110B l\u00e0 20464, gi\u1ea3i nh\u1ea5t v\u1ec1 10454 <\/span><\/span><\/span><\/p>\n Gh\u00e9p s\u1ed1 l\u1ea1i ta \u0111\u01b0\u1ee3c 2046410454, c\u1ed9ng theo Pascal:<\/span><\/span><\/span><\/p>\n 2046410454<\/span><\/span><\/span><\/p>\n 240051499<\/span><\/span><\/span><\/p>\n 64056538<\/span><\/span><\/span><\/p>\n 0451181<\/span><\/span><\/span><\/p>\n 496299<\/span><\/span><\/span><\/p>\n 35818<\/span><\/span><\/span><\/p>\n 8399<\/span><\/span><\/span><\/p>\n 128<\/span><\/span><\/span><\/p>\n 30<\/span><\/span><\/span><\/p>\n Ta c\u00f3 ng\u00e0y 24\/7\/2024 l\u00f4 v\u1ec1 30.<\/span><\/span><\/span><\/p>\n Tham kh\u1ea3o th\u00eam: <\/span>C\u00e1ch lu\u1eadn \u0111\u1ec1, t\u00ednh l\u00f4, b\u1eaft c\u1ea7u gi\u1ea3i \u0111\u1eb7c bi\u1ec7t XSMB chu\u1ea9n x\u00e1c, m\u1edbi nh\u1ea5t<\/span><\/span><\/strong><\/em><\/p>\n C\u00e1ch n\u00e0y \u00e1p d\u1ee5ng nh\u01b0 sau: D\u00f9ng s\u1ed1 \u0111\u1ea7u ti\u00ean c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 2 \u0111\u1ec3 l\u00e0m t\u1ed5ng chu\u1ea9n nu\u00f4i cho c\u1ea3 tu\u1ea7n. T\u1eeb \u0111\u00f3 l\u1eadp d\u00e0n \u0111\u1ec1 c\u1ee7a t\u1ed5ng n\u00e0y \u0111\u1ec3 nu\u00f4i l\u00f4, t\u1ef7 l\u1ec7 tr\u00fang l\u00e0 t\u01b0\u01a1ng \u0111\u1ed1i cao.<\/span><\/span><\/span><\/p>\n Ta c\u00f3 th\u1ee9 2 ng\u00e0y 17\/7\/2024 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 05488, l\u1ea5y 0 l\u00e0m t\u1ed5ng chu\u1ea9n ta c\u00f3 d\u00e0n sau:<\/span><\/span><\/span><\/p>\n 00, 191, 282, 373, 464, 55.<\/span><\/span><\/span><\/p>\n Ta c\u00f3 k\u1ebft qu\u1ea3:<\/span><\/span><\/span><\/p>\n Ng\u00e0y 18\/7 l\u00f4 55, 82, 91, 19 v\u1ec1.<\/span><\/span><\/span><\/p>\n Ng\u00e0y 19\/7 l\u00f4 55, 82 v\u1ec1, \u0111\u1ec1 n\u1ed5 37<\/span><\/span><\/span><\/p>\n Ng\u00e0y 20\/7 v\u1ec1 l\u00f4 19, 37, 55, 82, 91.<\/span><\/span><\/span><\/p>\n Ng\u00e0y 21\/7 v\u1ec1 l\u00f4 19, 55, 28, 91, \u0111\u1ec1 n\u1ed5 64.<\/span><\/span><\/span><\/p>\n Ng\u00e0y 22\/7 v\u1ec1 l\u00f4 91.<\/span><\/span><\/span><\/p>\n1. C\u00e1ch b\u1eaft c\u00e1c t\u1ed5ng trong l\u00f4 \u0111\u1ec1 d\u00f9ng b\u1ea1c nh\u1edb<\/span><\/strong><\/span><\/span><\/h2>\n
2. C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u00ednh l\u00f4<\/span><\/strong><\/span><\/span><\/h2>\n
3. C\u00e1ch b\u1eaft s\u1ed1 \u0111\u1ec1, l\u00f4 \u0111\u1ec1 d\u1ef1a v\u00e0o t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t<\/span><\/strong><\/span><\/span><\/h2>\n
4. C\u00e1ch b\u1eaft s\u1ed1 \u0111\u1ec1 hay b\u1eb1ng c\u1ed9ng quy lu\u1eadt Pascal<\/span><\/strong><\/span><\/span><\/h2>\n
5. C\u00e1ch b\u1eaft s\u1ed1 \u0111\u1ec1 mi\u1ec1n b\u1eafc th\u00f4ng qua s\u1ed1 \u0111\u1ea7u ti\u00ean gi\u1ea3i \u0111\u1eb7c bi\u1ec7t th\u1ee9 2<\/span><\/strong><\/span><\/span><\/h2>\n